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Here for Answers
- What are the possible gametes from each of the following
genotypes:
Remember,
alleles (different forms of the same gene) always come in pairs in a
diploid organism (e.g., you and me). Mendel determined that each allele
pair segregated during the formation of gametes by meiosis; this means
that each pair of alleles has to go into separate gametes.
- GG
- Gg
- GGRR
- GgRr
- GGRr
- GgRR
- GgRrXX
2. White flowers are recessive (r) to red flowers (R) in peas. You
cross a homozygous white flower plant with a homozygous red flower
plant. What color flowers will the offspring of this cross have?
3. Freckles are a dominant trait and non-freckles are recessive.
Fred has freckles and Jane doesn't. What is the probability that their
children will have freckles?
4. Cystic fibrosis is a recessive disease in humans. If neither of
your parents nor you have cystic fibrosis but your only brother does,
what is the probability that the next child born will have cystic
fibrosis?
5. Tongue rolling is a dominant trait. Can a husband and wife who
cannot roll their tongues produce a child who can roll his/her tongue?
6. Assuming complete dominance will occur, the offspring of the
cross Aa x Aa will show a phenotypic ratio of _______.
7. At a gene location on a human chromosome, a dominant allele
controls tongue-rolling ability. People who are homozygous for the
recessive allele cannot roll their tongue. At a different gene locus,
a dominant allele controls whether the earlobes will be attached or
detached; attached is recessive. Suppose a tongue-rolling, detached
ear lobed woman marries a man who has attached lopes and cannot roll
his tongue. Their first child has the phenotype of the father. Given
this outcome,
- What
are the genotypes of the father, mother and child? R = roll; r =
non-roll, A = detached; a=attached
- What
is the probability that a second child of theirs will have detached
earlobes and won't be able to roll his/her tongue?
Genetic
Problems Answers
- What are the possible gametes from each of the following
genotypes:
Remember, alleles (different forms of the same gene) always come in
pairs in a diploid organism (e.g., you and me). Mendel determined that
each allele pair segregated during the formation of gametes by
meiosis; this means that each pair of alleles has to go into separate
gametes.
- GG
- Gg
- GGRR
- GgRr
- GGRr
- GgRR
- GgRrXX
- White flowers are recessive (r) to red flowers (R) in peas. You
cross a homozygous white flower plant with a homozygous red flower
plant. What color flowers will the offspring of this cross have?
First you should determine the genotypes of the parents. The
red-flower parent's genotype is RR and the white-flower parent's
genotype is rr.
Next you need to determine the types of gametes (egg or pollen) each
parent can make. The red-flower plant can only make a gamete with a R
allele in it. The white flower plant can only make a gamete with a r
in it.
Now set
up a Punnett square
All of
your flower will be heterozygous (Rr) and red flowered!
- Freckles are a dominant trait and non-freckles are recessive.
Fred has freckles and Jane doesn't. What is the probability that their
children will have freckles?
First determine the genotypes of Fred and Jane. Can you determine
the exact genotype of Fred, the freckled parent? Fred could be FF or
Ff since freckles (F) is dominant! So given the information in the
question you cannot determine the probability that your children will
have freckles.
If Fred, who had freckles, had a mother who did not have freckles and
a father who did, now you could figure out what his genotype is as
follows. His mother has the ff genotype and his father has the F?
genotype. We don't need to worry about what the second allele is
because we know that he passed the F allele to Fred - that is why he
has freckles! And his mother passed the f allele to Fred, so Fred has
an Ff genotype.
Now what are the gametes?
Fred --> F or f
Jane --> f or f
Set up the Punnett square
50% of the children
would have freckles!
- Cystic fibrosis is a recessive disease in humans. If neither of
your parents nor you have cystic fibrosis but your only brother does,
what is the probability that the next child born will have cystic
fibrosis?
Let XC be normal allele and Xc represent
cystic fibrosis.
Your mother's genotype - XcXC and her gametes
are either Xc or XC
Your father's genotype - XCYand his gametes are
either Y or XC
How did I figure out your parent's genotype?
Set up the Punnett square
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Xc
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XC
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Y
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XcY
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XCY
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XC
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XcXC
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XCXC
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The probability is 25%
or 0.25 or 1/4- they all say the same thing.
- Tongue rolling is a dominant trait. Can a husband and wife who
cannot roll their tongues produce a child who can roll his/her tongue?
No. The husband and wife must both be homozygous recessive (rr) for
non-tongue rolling and cannot produce a child that is either
homozygous dominant (RR) or heterozygous (Rr).
- Assuming complete dominance will occur, the offspring of the
cross Aa x Aa will show a phenotypic ratio
of _______.
Set up the Punnett square
The phenotypic ratio
will be 3:1 (dominant phenotype:
recessive phenotype)
- At a gene location on a human chromosome, a dominant allele
controls tongue-rolling ability. People who are homozygous for the
recessive allele cannot roll their tongue. At a different gene locus,
a dominant allele controls whether the earlobes will be attached or
detached; attached is recessive. Suppose a tongue-rolling, detached
ear lobed woman marries a man who has attached lopes and cannot roll
his tongue. Their first child has the phenotype of the father. Given
this outcome,
What is the
genotypes of the father, mother and child? R = roll; r = non-roll, A =
detached; a=attached
Father is rraa
Mother is RrAa
Child is rraa
What is the
probability that a second child of theirs will have detached earlobes and
won't be able to roll his/her tongue?
First figure out what the gametes of the parents will be:
Father = ra
Mother = RA or Ra or rA or ra
Set up a Punnett square
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ra (sperm)
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RA (egg)
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RrAa
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Ra (egg)
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Rraa
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rA (egg)
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rrAa
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ra (egg)
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rraa
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25%
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